Beam Load Calculator

Find the maximum safe load on a wood, steel, or concrete beam.

Home 6 materials SF Stress + load
Rate this calculator · 4.5 (2)

Beam Load Capacity

Wood + steel + concrete · σ = M/W · point or uniform

Instructions — Beam Load Calculator

1

Set beam type and load

Pick simply-supported (two supports), cantilever (one fixed end), or fixed-fixed. Load is either a point load at center or a uniform distributed load (kN/m).

2

Enter span and load value

Span L is meters. Load is kN for point or kN/m for uniform. Default 20 kN over 5 m simulates a typical floor joist.

3

Pick material and section

Choose from S235/S355 steel, aluminum, pine/oak wood, or C30 concrete. Enter rectangular b × h in mm. The calc auto-computes I and W.

Formulas

Simply supported, point load center
$$ M_{max} = \frac{PL}{4} $$
P at midspan, two end supports. Max moment at midspan. Reactions = P/2 at each support.
Simply supported, uniform load
$$ M_{max} = \frac{wL^2}{8} $$
w in kN/m, max moment at midspan. Reactions = wL/2 each. The classic floor-joist formula.
Cantilever, point load at free end
$$ M_{max} = P \cdot L $$
Four times the moment of a simply-supported beam with the same load and span. Why balcony joists are oversized.
Bending stress (rectangular)
$$ \sigma = \frac{M}{W},\quad W = \frac{b h^2}{6} $$
σ is max bending stress at the extreme fiber. W is section modulus. Doubling h gives 4× the W and 4× the load capacity.
Allowable load back-solve
$$ P_{max} = \frac{\sigma_{allow} \cdot W \cdot k}{L^n} $$
k and n depend on beam type and load: 4 for SS-point, 8 for SS-uniform/L², 1 for cant-point, 2 for cant-uniform/L².

Reference

Allowable bending stresses
MaterialE (GPa)σ_allow (MPa)Notes
Steel S235210160Most common structural steel
Steel S355210235Higher-strength alloy
Aluminum 6061-T670110Lighter, less stiff
Pine (softwood)1110Construction-grade lumber
Oak (hardwood)1312Premium furniture and beams
Concrete C30/373318 (comp)Tension requires rebar

Article — Beam Load Calculator

Beam Load Calculator: Capacity, Moment, and Stress

Maximum beam load comes from σ_allow · W ÷ L (with a factor depending on beam type). A simply-supported steel S235 beam, 100×200 mm rectangular, 5 m span, can carry roughly 85 kN as a center point load or 34 kN/m as a distributed load before bending stress hits the allowable 160 MPa.

This calculator handles the three most common beam configurations — simply supported, cantilever, fixed-fixed — under either a point load or a uniform distributed load. It returns max moment, shear, bending stress, the section modulus and moment of inertia of a rectangular cross-section, and the maximum safe load that keeps stress within the allowable limit for your chosen material.

What is beam load?

A beam load is any force applied transverse to a beam's length: gravity on a floor joist, snow on a roof rafter, traffic on a bridge stringer. Internally the beam responds with shear forces and bending moments. Bending stress, computed from the moment and the section's geometry, is what eventually breaks the beam if loads grow too large.

Three quantities drive the analysis: the maximum bending moment M_max, the section modulus W (a geometric property of the cross-section), and the allowable bending stress σ_allow for the chosen material. The governing inequality is σ = M/W ≤ σ_allow.

Did you know

Galileo Galilei wrote the first known analysis of beam strength in Two New Sciences (1638). He got the formula wrong by a factor of three — he assumed neutral axis at the bottom rather than the centroid — but he established the field. Mariotte corrected the math in 1686.

Beam load formulas

The maximum moment depends on beam type (support conditions) and load shape. Six combinations cover most practical cases.

Maximum bending moments
Simply supp., point M = PL/4
Simply supp., uniform M = wL²/8
Cantilever, point M = PL
Cantilever, uniform M = wL²/2
Fixed-fixed, point M = PL/8
Fixed-fixed, uniform M = wL²/12

From the moment, stress follows directly: σ = M / W. To back-solve for the maximum allowable load, set σ = σ_allow and rearrange. For a simply-supported beam with point load: P_max = 4 · σ_allow · W / L.

Beam types and loading

Most residential and small-commercial design uses three beam types and two loadings. They cover floor joists, roof rafters, headers, balconies, and most beams in framed buildings.

  • Simply supported: Two end supports, free to rotate. Floor joists, roof rafters, single-span girders.
  • Cantilever: One fixed end, one free. Balcony joists, awnings, retaining-wall stems.
  • Fixed-fixed: Rigid connections at both ends. Multi-bay continuous beams approximate this.
  • Point load: Concentrated force at a specific location. A column landing on a beam.
  • Uniform load: Force per unit length. Floor decking, snow, self-weight of the beam.
  • Triangular load: Varies linearly. Hydrostatic pressure, snow drifting against a wall.

Bending stress and section modulus

The fundamental bending equation is σ = M·y/I, where y is distance from the neutral axis and I is moment of inertia. At the extreme fiber, y = h/2 for a symmetric section. Substituting and grouping gives σ_max = M / W with W = I / (h/2) = bh²/6 for a rectangle.

Geometry has a much bigger lever than material. Doubling the depth h of a rectangular section gives 4× the moment of inertia (since I scales as h³), 4× the section modulus, and 4× the load capacity at the same stress. Doubling the width b only doubles capacity. This is why I-beams concentrate material in the flanges, far from the neutral axis: every kilogram added at h/2 is four times more effective than the same kilogram at the neutral axis.

Section modulus shortcuts
Rectangle b × h W = bh²/6
Solid circle d W = π d³/32
Hollow tube D, t W ≈ π D² t / 4
I-beam (tabulated) see manufacturer

Beam load by material

Allowable stress varies by an order of magnitude across structural materials.

Pine
σ ≈ 10 MPa
cheap, easy to work
Steel S235
σ ≈ 160 MPa
16× pine, more expensive

Steel buys 16× the capacity per cross-section area compared with pine. Aluminum sits at 110 MPa, between steel and wood — useful where weight matters more than absolute strength. Concrete is asymmetric: roughly 18 MPa compressive but near zero tension, which is why reinforced concrete uses steel rebar to carry tension while the concrete handles compression.

Beam load design process

The structural design workflow for a beam follows the same six steps regardless of material.

  1. Determine loads — both dead (permanent) and live (variable). Use code values like ASCE 7 or EN 1991.
  2. Compute max moment M_max using the appropriate formula for support type and load shape.
  3. Solve for required section modulus W ≥ M_max / σ_allow.
  4. Pick a section whose tabulated W exceeds the requirement. Round up to standard sizes.
  5. Verify shear (V_max divided by shear area) and deflection (under L/360 for floors).
  6. Detail connections and lateral bracing. Beams that fail laterally before flexure are common in slender steel sections.
Strength and deflection are separate checks

A beam can pass the bending stress check yet fail deflection. Long shallow beams (especially wood) often govern by deflection: σ may be only 60% of allowable, but δ exceeds L/360 and the floor feels bouncy or drywall above cracks. Always run both calcs.

Common beam-load mistakes

Five recurring errors show up across decades of structural engineering practice.

  • Wrong support model: Treating a partially-restrained connection as fully fixed (or vice versa). Real connections sit somewhere in between.
  • Forgetting self-weight: For long beams self-weight is 10-30% of total load.
  • Skipping shear check: Short, deep beams may fail in shear before bending. Always verify τ = V/A_shear.
  • Wrong section axis: Strong axis vs. weak axis bending — orientation matters and changes I by a factor of 10+.
  • Ignoring deflection: Floor vibration and drywall cracking come from deflection, not strength.
  • Using nominal lumber dimensions: A 2x10 is actually 1.5x9.25 inches. Use actual dimensions in math.

Beam load codes and standards

Five major code families govern beam design worldwide. They differ in detail but converge on similar safety levels.

  • USA: ASCE 7 (loads), AISC 360 (steel), NDS (wood), ACI 318 (concrete).
  • Europe: Eurocode 1 (loads), Eurocode 3 (steel), Eurocode 5 (timber), Eurocode 2 (concrete).
  • UK: Pre-Eurocode BS 5950 (steel), now superseded by Eurocodes since 2010.
  • Canada: NBC plus CSA S16 (steel), CSA O86 (wood), CSA A23.3 (concrete).
  • Japan: Architectural Institute of Japan (AIJ) standards plus the Building Standard Law.

FAQ

For a point load P at midspan: M_max = PL/4. For a uniform distributed load w over the full length: M_max = wL²/8. For a 20 kN point load on a 5 m span, M_max = 25 kN·m. These are the two most-used formulas in structural design.
Three steps. (1) Compute M_max from the load and span. (2) Compute required section modulus W ≥ M_max / σ_allow. (3) Pick a section (W-shape, I-beam, lumber) whose tabulated W exceeds the requirement. Verify deflection and shear separately.
W = I / c, where I is moment of inertia and c is the distance from neutral axis to extreme fiber. For a rectangular section b × h: W = bh²/6. Doubling the depth h gives 4× the W — the cheapest way to add capacity is taller, not wider.
For the same point load at the free end, a cantilever's max moment is PL — four times the PL/4 of a simply-supported beam with the same load at midspan. The bending stress is also 4×. This is why balcony joists are usually 1.5–2× the depth of interior floor joists.
Dead load is permanent: the weight of the structure itself, fixed partitions, mechanical equipment. Live load is variable: people, furniture, vehicles, snow. ASCE 7 and EN 1991-1-1 list typical values (e.g., 2.0 kN/m² for residential floors, 5.0 kN/m² for assembly areas).
Strength (stress check) and serviceability (deflection check) are two separate criteria. Compute max deflection (e.g., 5wL⁴/384EI for SS-uniform) and verify it stays below L/360 for floors or L/240 for roofs. A beam can pass stress yet fail deflection — both must check.
Only if it's under ~5% of the applied load. For a 5 m timber 100×200 beam at 500 kg/m³, self-weight = 0.1 kN/m. Compared with a 5 kN/m floor load that's 2% and can be skipped. For a long steel beam or a thin cantilever, include self-weight as additional uniform load.
Allowable-stress design (ASD) builds the factor into σ_allow. For steel S235 the yield is 235 MPa but σ_allow is 160 MPa — a built-in 1.47 factor. Load and Resistance Factor Design (LRFD) instead applies factors to loads (1.2 dead + 1.6 live) and resistance (0.9 for flexure). Both systems target similar reliability.