Buoyancy Calculator (Archimedes Principle)

Apply Archimedes principle to find buoyant force, apparent weight, and float-or-sink behavior.

Science Floats or sinks Mercury · air
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F_b = ρ × V × g

Archimedes principle · float / sink check

Instructions — Buoyancy Calculator (Archimedes Principle)

1

Pick fluid and gravity

Default is fresh water on Earth. Switch to sea water (1025 kg/m³), mercury (13546), or air (1.225) for buoyancy in gases. Gravity dropdown handles other worlds.

2

Enter the object volume

Volume in cubic meters (m³). 1 L = 0.001 m³. The percent-submerged field defaults to 100 — partially floating objects use a smaller value.

3

Add mass (optional)

Type the object's mass to see weight, apparent weight in fluid, and a float / sink verdict based on density comparison.

Formulas

Buoyant Force
$$ F_b = \rho_{fluid} \cdot V_{disp} \cdot g $$
Upward force equals the weight of fluid pushed aside. For 1 m³ in fresh water: 1000 × 1 × 9.81 = 9810 N.
Float Condition
$$ \rho_{object} < \rho_{fluid} $$
Objects float when their average density is less than the surrounding fluid. Otherwise they sink.
Apparent Weight
$$ W_{app} = W - F_b $$
Submerged weight. A 10 kg lead block (W = 98.1 N) loses about 8.7 N in water, weighing 89.4 N underwater.
Equilibrium Float Depth
$$ \frac{V_{disp}}{V_{total}} = \frac{\rho_{object}}{\rho_{fluid}} $$
Ice (917 / 1000) shows 8.3% above water. Saltwater raises a swimmer's exposed body fraction.
Specific Gravity
$$ SG = \frac{\rho_{object}}{\rho_{water}} $$
SG < 1 → floats; SG > 1 → sinks. Used in hydrometers to measure battery acid, fuel, and brewing wort.
In Air
$$ F_b = \rho_{air} V g \approx 0.012 V \,\text{N/L} $$
Even solid objects experience air buoyancy. Precision balances correct for it. A 1 m³ helium balloon lifts about 11 N.

Reference

Fluid Density Table
FluidDensity (kg/m³)Notes
Fresh water (4°C)1000Reference value
Sea water (15°C)10253.5% salinity
Dead Sea1240~33% dissolved salt
Ethanol789Pure, 20°C
Petroleum / diesel800–860Floats on water
Honey1420Densest common food liquid
Mercury13546Iron floats on mercury
Air (STP)1.225Sea level, 15°C
Helium0.166Lifts in air

Article — Buoyancy Calculator (Archimedes Principle)

Buoyancy Calculator (Archimedes Principle)

Buoyant force equals the weight of fluid displaced: F_b = ρ × V × g. A 1 m³ object in fresh water gets 9810 N of lift. The same object in sea water (1025 kg/m³) gets 10,050 N. Whether it floats depends on whether F_b can balance the object's own weight.

What buoyancy is

Buoyancy is the upward push a fluid exerts on anything immersed in it. The push exists because fluid pressure increases with depth — the bottom of a submerged object sits in higher-pressure fluid than the top, and the difference is a net upward force. Archimedes proved around 250 BC that this net force exactly equals the weight of the fluid that the object pushes aside. Two and a half millennia later, no experiment has found a violation.

The same principle holds in liquids and gases. Air buoyancy is normally negligible because air is light, but for a hot-air balloon or helium balloon it dominates. In water it dominates for any object less dense than water — wood, ice, boats. In mercury, even cast iron floats.

Did you know

The Greek king Hiero II reportedly asked Archimedes to detect whether a goldsmith had cheated on a crown. Archimedes used buoyancy: a pure-gold crown of known weight would displace exactly the same volume as a pure-gold lump of the same weight. If the crown displaced more, it was alloyed with silver. The story is the original recorded use of nondestructive density testing.

The buoyancy formula

F_b = ρ × V × g. Three inputs, one output. ρ is the density of the fluid in kg/m³. V is the displaced volume — for a fully submerged object, that equals the object's volume; for a partially submerged floater, it equals just the underwater portion. g is gravitational acceleration, 9.81 m/s² on Earth.

The equation is dimensionally clean: kg/m³ times m³ times m/s² gives kg·m/s² = N. There is no fitted constant, no correction term, no temperature factor. Real-world buoyancy calculations only get messy when ρ varies (warm water versus cold) or when V is hard to measure (irregular shapes need water-displacement measurement).

Will it float or sink?

The float-or-sink rule reduces to a density comparison. If the object's average density is less than the surrounding fluid, it floats. If greater, it sinks. If equal, it hovers — neutral buoyancy.

Float-or-sink in fresh water
Cork (240) Floats — 76% above
Ice (917) Floats — 8% above
Water (1000) Neutral
Concrete (2400) Sinks
Iron (7870) Sinks
Gold (19300) Sinks fast

For floating objects, the submerged fraction equals the density ratio. Ice with 917 kg/m³ sits 91.7% underwater in fresh water — the visible part of an iceberg is the famous one-eighth, which is roughly correct (in sea water, ice is 10.5% above the surface).

Buoyancy in different fluids

Switch fluids and the buoyant force on the same object scales linearly with fluid density. Sea water gives 2.5% more lift than fresh water, which is why swimmers find ocean swimming slightly easier. The Dead Sea (1240 kg/m³) gives 24% more lift; people float so high there that drowning is nearly impossible by accident.

Fresh water
1000 kg/m³
reference fluid
Dead Sea
1240 kg/m³
24% more lift

Mercury at 13,546 kg/m³ lifts iron blocks. A solid iron cube placed on mercury floats with about 42% of its volume above the surface, because iron (7870) is only 58% as dense as mercury. Demonstrations use this to startle students — heavy metal lifting heavier metal seems wrong until the density numbers settle the question.

Buoyancy in air versus water

Air buoyancy is real but usually small. Sea-level air has density 1.225 kg/m³, roughly 1/800 of water. A 1 m³ object in air gets about 12 N of lift — under a kilogram of equivalent weight. For people and most objects, that lift is buried in the noise of gravity, friction, and air drag.

When buoyancy in air does matter: precision weighing. A laboratory scale measuring sub-milligram differences must correct for air buoyancy because a mass of one density displaces more air than a mass of higher density. NIST publishes correction formulas; calibration of national standards uses them routinely.

Tip

Helium balloons rise because helium (0.166 kg/m³) is less dense than air. A 1 m³ helium balloon experiences 12 N of air buoyancy, but its own weight (helium + skin) is only about 1 N. Net upward force: roughly 11 N. That lifts a small payload — the basis of weather radiosondes and party balloon trains.

Apparent weight under water

Submerging an object reduces its felt weight by the buoyant force. A 10 kg iron block weighs 98.1 N in air. Its volume is 10 / 7870 = 1.27 × 10⁻³ m³. In water that volume gets ρVg = 1000 × 0.00127 × 9.81 = 12.5 N of buoyancy. Apparent weight in water: 98.1 − 12.5 = 85.6 N. The block still feels heavy and still sinks, but it's noticeably lighter under water.

Divers exploit this. Neutral-buoyancy training tanks let astronauts simulate space-walks: ballast brings the suit + diver to ρ_water, and net force is near zero. Movement in a neutral-buoyancy tank closely resembles weightlessness, which is why NASA built one.

Common buoyancy mistakes

The four classic errors.

ρ_fluid, not ρ_object

The density in F_b = ρVg is the fluid's density, not the object's. Using the object's density gives an answer with the right units but the wrong physics. Always pull ρ from the surrounding medium.

Second, ignoring partial submersion. A floating boat displaces only the underwater volume, not its total hull volume. Treating a floater as fully submerged overestimates F_b by a factor of (total / submerged) volume.

Third, confusing buoyancy with weight. Buoyancy is the upward force; weight is the downward gravity force. They are independent — gravity does not change with submersion, only the apparent weight (net force) does.

Fourth, assuming buoyancy changes with depth in water. It doesn't. F_b depends on displaced volume and fluid density; both are constant for water at any reasonable depth.

FAQ

The buoyant force on a submerged object equals the weight of fluid it displaces. Mathematically: F_b = ρ_fluid × V_displaced × g. Stated by Archimedes around 250 BC, it explains why ships float, balloons rise, and lead sinks. The principle works for any fluid, liquid or gas.
F_b = ρ × V × g. Use the density of the fluid (not the object) in kg/m³, the displaced volume in m³, and g = 9.81 m/s² on Earth. Example: a 0.1 m³ object fully submerged in sea water has F_b = 1025 × 0.1 × 9.81 = 1005 N upward.
Compare the average densities. If ρ_object < ρ_fluid, the object floats; if ρ_object > ρ_fluid, it sinks. A 5 cm wooden cube (ρ ≈ 600 kg/m³) floats in water; the same cube in iron (7870 kg/m³) sinks. Hollow shapes (boats) have low average density because they enclose air.
A ship hull is mostly hollow. Steel itself has density 7870 kg/m³ — far above water's 1000 — but the ship as a whole (steel + enclosed air) has average density below 1000 kg/m³. Once water breaches the hull and air escapes, the average density rises and the ship sinks. This is exactly what happens to flooded vessels.
W_apparent = W − F_b. The object's normal weight minus the buoyant force. A 10 kg iron block weighs 98.1 N in air. Submerged in water it displaces 0.00127 m³, getting 12.5 N of buoyant force, so apparent weight drops to 85.6 N. The block still sinks because apparent weight is positive.
In an incompressible fluid like water, no. F_b depends on displaced volume and fluid density, both of which are roughly constant. In a compressible fluid like air, F_b decreases at altitude because air density drops. This is why weather balloons rise to a ceiling — when ambient air density equals the balloon's average density, lift stops.
Its water density is about 1240 kg/m³ thanks to dissolved salts — 24% denser than fresh water and 21% denser than ocean. Buoyant force per displaced volume scales with ρ_fluid, so swimmers float higher. Roughly a third of the body sits above water versus a tenth in fresh water. The lift makes swimming feel effortless.
Usually no, but for precision: a 1 kg steel mass in air feels lift of 1.2 mN — about 0.012% of its weight. Precision balances over 0.001 g resolution correct for this. The effect matters at the milligram level, in standard weight calibration, and when comparing materials of very different density on the same balance.
Ballast tanks. Filling them with seawater raises the sub's average density and lets it sink. Blowing compressed air into the tanks pushes water out, lowers average density, and the sub rises. Neutral buoyancy is achieved when ρ_sub equals ρ_seawater, allowing the vessel to hover at depth without using propulsion.