Electrical Power Calculator

Calculate electrical power, voltage, current, or resistance using Ohm and Joule laws.

Science 6 input modes kWh + cost
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Electrical power solver

P = V × I = I² × R = V² / R

Instructions — Electrical Power Calculator

  1. Pick which two values you know — voltage and current (V & I), current and resistance (I & R), voltage and resistance (V & R), or power with one other (P & V / I / R).
  2. Enter the two known values. The calculator fills in the remaining quantities using Ohm law and the power equations.
  3. Optionally enter a run time in hours to get energy in kilowatt-hours and an estimated electricity cost.
  4. Read the full set: voltage, current, resistance, power in W / kW / hp, energy, and cost at $0.16/kWh (US average).

Formulas

Ohm law links voltage, current, and resistance:

$$V = I \cdot R$$

Joule law gives power as voltage times current:

$$P = V \cdot I$$

Equivalent forms using Ohm law:

$$P = I^2 \cdot R = \frac{V^2}{R}$$

Energy is power times time:

$$E = P \cdot t$$

1 watt-hour = 3,600 J. 1 kWh = 3.6 MJ.

Reference

  • 1 W = 1 J/s = 1 V·A (volt-ampere)
  • 1 horsepower = 745.7 W = 0.7457 kW
  • Standard household outlet: 120 V × 15 A = 1,800 W (US); 230 V × 13 A = 2,990 W (UK/EU)
  • LED bulb: 8–15 W; incandescent equivalent: 60 W
  • Laptop: 30–90 W; gaming desktop: 300–800 W
  • Air conditioner: 1,000–2,500 W; electric vehicle charging: 7,000–22,000 W (Level 2)
  • Typical residential service: 100–200 A at 240 V = 24–48 kW available
  • US average electricity cost: $0.16 per kWh (2024); EU average: €0.27 per kWh

Article — Electrical Power Calculator

Electrical power calculator

Electrical power is the rate at which electrical energy is transferred, measured in watts. The fundamental equation is P = V × I — volts times amps. Combined with Ohm law, this also writes as P = I² × R and P = V²/R. A 1,500 W toaster pulls 12.5 A from a US 120 V outlet, or 6.5 A from a UK 230 V outlet. One kilowatt sustained for one hour equals one kilowatt-hour of energy.

Three equivalent formulas mean you can solve for power from any two of voltage, current, and resistance. The right form to use depends on what you measure. A multimeter reads current and resistance? Use P = I²R. You know the appliance label voltage and want to predict current draw? Use I = P/V. The calculator above handles all six pair combinations.

What is electrical power?

Electrical power is the rate at which energy moves through a circuit. One watt is one joule per second. When a charge moves through a potential difference, it gains or loses energy proportional to the voltage; the rate at which charge moves is current; so power equals the product. A 100 W incandescent bulb converts 100 joules of electrical energy into heat and a small amount of light every second.

The unit is named for James Watt, the Scottish engineer who improved the steam engine in the 1770s and rationalised power measurement across the industries that adopted it. The watt became an SI base-derived unit in 1960. One horsepower equals 745.7 W by exact definition — handy for converting between motor specs in different unit systems.

Electrical power formulas

Three equivalent power equations follow from Ohm law and the basic P = VI relation.

Electrical power formulas
P = V × I fundamental, watts = volts × amperes
P = I² × R using Ohm law V = IR
P = V² / R using Ohm law I = V/R
E = P × t energy = power × time
1 kWh = 3.6 MJ = 3,600,000 J billing unit

The I²R form matters in safety calculations. Power dissipated as heat in a wire scales with the square of current. Halving the current cuts heat dissipation by a factor of four — which is why long-distance transmission uses high voltage to minimise current and resistive losses. The same energy delivered at 500 kV versus 13 kV experiences roughly 1,500 times less I²R loss in the conductor.

Electrical power vs energy

Power and energy are different quantities. Power is the instantaneous rate; energy is the integral of power over time. A 2 kW kettle has 2,000 watts of power. Running it for 3 minutes consumes 2,000 × (3/60) = 100 Wh = 0.1 kWh of energy. Confusing the two is the most common conceptual error in residential electricity.

Utilities bill for energy, not power, because energy is what they actually deliver. A device that pulls 100 W for 24 hours uses the same energy (2.4 kWh) as a device that pulls 2,400 W for 1 hour. But the 2,400 W device requires a circuit capable of delivering 2,400 W instantaneously — power, not energy, is what sizes wires and breakers.

Did you know

Three Mile Island Unit 1, a typical nuclear reactor, generates about 800 MW of electrical power continuously. That is the same as 8 million 100 W light bulbs running simultaneously, or 320,000 average US homes' continuous load. The plant produces roughly 6,400 GWh per year — enough energy to power a small country for several days, or to deliver 23 quadrillion joules of electrical energy (23 petajoules).

Electrical power by appliance

Typical power draws for household and industrial electrical loads, useful for sizing circuits and estimating energy use.

  • LED bulb (60 W equivalent): 8–10 W. About 1/6 the energy of incandescent.
  • Laptop: 30–90 W depending on workload. Idle is closer to 15 W.
  • WiFi router: 5–15 W. Always on, so 50–130 kWh/year.
  • Refrigerator: 100–200 W average, peaking at 600 W on compressor start.
  • Microwave oven: 800–1,500 W output, 1,200–2,000 W input.
  • Toaster, kettle, hairdryer: 1,000–1,800 W — close to outlet circuit limit.
  • Window AC unit: 800–1,500 W; central AC: 3,000–5,000 W.
  • Electric water heater: 4,500–5,500 W; on for 3–5 hours per day.
  • Electric vehicle Level 2 charging: 7,000–11,000 W (32–48 A at 240 V).
  • House service (US, 200 A at 240 V): 48,000 W theoretical peak.

AC vs DC electrical power

Direct current power is straightforward: P = V × I, both constant, both producing real power that does work. Alternating current adds complexity. Voltage and current oscillate sinusoidally; if they peak at the same moment, all the power is "real" and dissipates as heat or work. If they are out of phase — common with motors, transformers, and electronic loads — some current shuttles back and forth without doing work.

DC
P = VI
simple product
AC
P = VI cos(φ)
power factor matters

The three AC power quantities are real power P = VI cos(φ) measured in watts, reactive power Q = VI sin(φ) measured in volt-amperes-reactive (VAR), and apparent power S = VI measured in volt-amperes (VA). The power factor cos(φ) ranges from 0 (purely reactive) to 1 (purely resistive). Resistive loads like incandescent bulbs and heaters have power factor ≈ 1. Induction motors run 0.7–0.9; electronic power supplies vary widely.

Electrical power cost of running an appliance

Cost = power (kW) × hours × rate. At the US average of $0.16/kWh, a 100 W bulb running 5 hours a day costs 0.1 × 5 × 365 × $0.16 = $29.20 per year. Swap for a 10 W LED and the same usage costs $2.92/year — a $26 annual saving per bulb.

Watts on the label is not always watts at the wall

Audio amplifier "1,000 W" specs often refer to peak music power or output power into a low-impedance load — not the wall draw. A real 1,000 W RMS amplifier into 8 Ω might draw 1,400–1,800 W from the wall at full output, plus 50–100 W at idle. Always check whether a wattage rating is input, output, peak, or RMS before sizing circuits or estimating cost.

Common electrical power mistakes

Tip

If your electrical-power calculation gives nonsense, check whether you mixed RMS and peak voltages. Standard "120 V" or "230 V" outlet voltages are RMS — the equivalent DC voltage that delivers the same power. Peak values are 1.414× the RMS, so a US outlet swings between +170 V and −170 V at 60 Hz, not ±120 V.

The first common mistake is treating power and energy as interchangeable. A "10 kW" battery is meaningless without a duration — 10 kW for one hour is 10 kWh of energy, but the same 10 kWh battery could deliver 1 kW for 10 hours. Power rates how fast; energy counts how much.

The second mistake is ignoring power factor in motor circuits. A 1 hp (746 W real) motor with a power factor of 0.8 draws 933 VA, not 746 VA. If you size the supply wiring based on real power alone, the actual current is 933 / V (e.g. 7.8 A at 120 V), and the wire can overheat. Utility-scale loads with poor power factor pay penalty rates because they hog circuit capacity without doing proportional work.

A third mistake is forgetting voltage drop in long runs. Resistive losses in feed wires reduce voltage at the load, and lower voltage at fixed resistance means lower power. A 10% voltage drop becomes 19% power loss because P = V²/R. NEC guidance limits voltage drop to 3% for branch circuits and 5% total, partly for performance and partly for safety.

FAQ

The fundamental equation is P = V × I, where P is power in watts, V is voltage in volts, and I is current in amperes. Using Ohm law (V = IR), this rewrites as P = I² × R or P = V²/R. All three forms give the same result — choose whichever uses the two values you actually know.
Use P = I² × R. Square the current and multiply by resistance. Example: a 2 A current through a 100 Ω resistor dissipates 4 × 100 = 400 W as heat. This form is most useful when you know the current and resistance but not the voltage drop across the element.
A kilowatt is a rate of energy use — 1,000 joules per second. A kilowatt-hour is an amount of energy — 1 kW sustained for 1 hour, which equals 3.6 million joules. Utilities bill for kilowatt-hours because they sell energy, not power. A 1 kW heater running for 2 hours consumes 2 kWh.
A US single-family home averages around 1.2 kW continuous (10,500 kWh per year). Peak demand on a hot afternoon with AC running can hit 5–8 kW. A 200-amp service at 240 V allows up to 48 kW theoretical maximum but in practice loads are staggered.
DC (direct current) power follows P = V × I directly. AC (alternating current) power has three flavours: real power P = V × I × cos(φ), apparent power S = V × I (in volt-amperes), and reactive power Q = V × I × sin(φ). The cos(φ) factor — the power factor — accounts for current and voltage being out of phase in inductive or capacitive loads.
Divide watts by 745.7 to get mechanical horsepower (used for motors, vehicles, pumps). Example: a 1,500 W vacuum cleaner motor is 1500/745.7 ≈ 2.01 hp. The conversion is exact by the 1948 SI definition: 1 hp = 550 ft·lb/s = 745.6999 W.
Trick question — heaters with fixed resistance pull less current at lower voltage (I = V/R) and dissipate less power (P = V²/R). What does happen: heaters with thermostatic control run longer at lower voltage to deliver the same energy. Inverter-driven loads (heat pumps, EV chargers) can hold constant power output by drawing more current as voltage sags.
Utilities bill for kilowatt-hours: kWh = (watts × hours) / 1000. A 100 W bulb burning 10 hours uses 1 kWh. At the US average $0.16/kWh, that costs about 16 cents. For an electric water heater at 4,500 W running 4 hours a day, that is 18 kWh/day × $0.16 = $2.88/day — over $1,000 a year if always-on.