Molality Calculator

Compute molality (m, mol/kg) from solute mass or moles and solvent mass.

Science mol/kg 3 modes 10 substances
Rate this calculator · 3.5 (2)

Molality Calculator

3 modes - 10 substances - mol/kg

Instructions — Molality Calculator

Molality (m) is moles of solute per kilogram of solvent. Unlike molarity it does not change with temperature.

  1. Mass to molality: enter solute mass, molar mass, and solvent mass. The calculator computes moles and divides by kilograms of solvent.
  2. Moles to molality: skip the molar-mass step if moles are already known.
  3. Molality to mass needed: enter a target molality and solvent mass; the calculator returns the grams of solute required.

The substance selector autofills common molar masses (NaCl, glucose, urea, CaCl2 and others). Solvent mass is entered in grams and converted internally to kilograms.

Formulas

Definition (note: mass of solvent, not solution):

$$ m = \frac{n_{solute}}{m_{solvent,\text{kg}}} $$

From solute mass:

$$ m = \frac{m_{solute}}{M_r \cdot m_{solvent,\text{kg}}} $$

Mass of solute for a target molality:

$$ m_{solute} = m \cdot m_{solvent,\text{kg}} \cdot M_r $$

Freezing-point depression (a key use of molality):

$$ \Delta T_f = K_f \cdot m \cdot i $$

where K_f is the cryoscopic constant of the solvent and i is the van't Hoff factor (1 for non-electrolytes, ~2 for NaCl, ~3 for CaCl2).

Reference

Common solvent cryoscopic and ebullioscopic constants:

SolventK_f (C kg/mol)K_b (C kg/mol)
Water1.860.512
Benzene5.122.53
Cyclohexane20.22.79
Camphor40.05.95
Acetic acid3.903.07

Typical molalities in solutions:

SolutionMolality (mol/kg)
0.9% saline (NaCl)0.154
Seawater~0.6
Standard freezing-point lab (1 m NaCl)1.0
Saturated sucrose at 25 C~6
Saturated NaCl at 25 C~6.1

Article — Molality Calculator

Molality Calculator: m = mol Solute per kg Solvent

Molality (m) is moles of solute per kilogram of solvent: m = n / m_solvent(kg). A 1 molal NaCl solution contains 1 mole (58.44 g) of NaCl dissolved in exactly 1 kilogram of water. Unlike molarity, molality does not change with temperature because mass does not expand or contract with heat.

Molality is the natural unit for thermodynamic problems and for colligative properties: freezing-point depression, boiling-point elevation, osmotic pressure, and vapor-pressure lowering. It is the unit that physical chemists reach for when temperature varies during the calculation.

What molality measures

Molality describes how concentrated a solution is in terms of particles relative to the solvent. The defining unit is mol per kilogram of solvent, not solution. This distinction is essential: 1 kg of pure water plus 58.44 g of dissolved NaCl is 1 m, not the entire 1058 g of mixture in the denominator.

The unit was introduced in the late 19th century specifically to handle problems where the solvent expands or contracts with temperature. Molarity uses solution volume, which is temperature-dependent; molality uses solvent mass, which is invariant. For precise thermodynamic measurements at varying temperatures, molality is the right tool.

The molality formula step by step

Molality formulas
m = n / m_solvent(kg) moles per kg of solvent
m = m_solute / (M_r · m_solvent(kg)) from mass
m_solute = m · m_solvent(kg) · M_r mass needed
ΔT_f = K_f · m · i freezing-point depression

The calculation has three steps when starting from grams: convert solute mass to moles using molar mass, convert solvent mass from grams to kilograms, and divide. For a solid like NaCl: 5.844 g / 58.44 g/mol = 0.1 mol; divide by 0.500 kg of water; molality = 0.2 mol/kg.

Molality versus molarity

The two concentration units differ by one letter and one critical word. Molarity uses solution volume; molality uses solvent mass. For dilute aqueous solutions the numerical values are nearly identical (1 L of water weighs about 1 kg), but they diverge in three situations: concentrated solutions, non-aqueous solvents, and temperature-dependent problems.

PropertyMolarity (M)Molality (m)
Unitmol / L of solutionmol / kg of solvent
Temperature-dependentYesNo
Ease of preparationEasier (volumetric flask)Harder (analytical balance)
Used inLab work, biology, pharmacyThermodynamics, colligative
Did you know

Antifreeze in car radiators works by molality. Ethylene glycol depresses water's freezing point: a 50/50 (volume) glycol-water mix is about 18 molal, which lowers the freezing point by roughly 35 C below 0 C. Without it, every northern winter would crack engine blocks.

Molality and colligative properties

Colligative properties depend only on the number of dissolved particles, not their identity. There are four classic ones:

Freezing-point depression: ΔT_f = K_f · m · i. Water's K_f is 1.86 C kg/mol. A 1 m solution of sugar (i = 1) freezes 1.86 C below 0 C. A 1 m solution of NaCl (i ~ 2) freezes about 3.7 C below 0 C. The dissolved ions split into more particles than the formula suggests.

Boiling-point elevation: ΔT_b = K_b · m · i. The same math with K_b = 0.512 C kg/mol for water. A 1 m sucrose solution boils about 0.5 C above 100 C.

Osmotic pressure: Π = m R T i. The pressure that develops across a semipermeable membrane separating pure solvent from solution. Critical for kidney function, IV fluid design, and food preservation by salt or sugar.

Vapor-pressure lowering (Raoult's law). The mole fraction of solvent in the solution determines the vapor pressure ratio.

Molality worked examples

Example 1. Dissolving 14.61 g NaCl (Mr 58.44) in 250 g of water. Moles = 14.61 / 58.44 = 0.25 mol. Solvent in kg = 0.250 kg. m = 0.25 / 0.250 = 1.0 mol/kg. A 1 molal NaCl solution.

Example 2. Preparing 500 g of water containing 0.5 molal urea (Mr 60.06). Moles needed = 0.5 × 0.500 = 0.25 mol. Mass needed = 0.25 × 60.06 = 15.0 g of urea.

Example 3. How far does a 0.3 m CaCl2 solution drop the freezing point of water? i ~ 2.7 (slightly less than 3 due to ion pairing). ΔT_f = 1.86 × 0.3 × 2.7 = 1.5 C. The brine freezes around -1.5 C.

Common molality values

  • 0.154 m NaCl: isotonic saline (matches blood)
  • ~0.6 m: seawater (total dissolved salts)
  • 1.0 m: classic teaching example
  • ~6 m: saturated NaCl in water at 25 C
  • ~6 m: saturated sucrose in water at 25 C
  • ~8 m: 50/50 glycol antifreeze
  • ~10 m: concentrated salt brines for road treatment

Molality calculation mistakes

Solvent mass, not solution mass

The denominator is the mass of pure solvent, not the total mass of the solution. A 100 g solution containing 5 g of solute has 95 g of solvent in the denominator. Using 100 g shrinks the calculated molality by about 5%. This is the leading molality error.

Other regular slips: forgetting to convert grams of solvent to kilograms (a factor-of-1000 error), confusing molality with molarity in a problem that uses solvent volume, ignoring the van't Hoff factor for ionic compounds in colligative calculations, and assuming i = 2 exactly for NaCl when it is closer to 1.9 in dilute solution because of weak ion pairing.

Where molality matters most

For routine analytical work in chemistry and biology, molarity is the default. Molality earns its keep in three places:

Antifreeze chemistry: every glycol-water blend specification is implicitly a molality calculation, because the freezing-point depression formula uses m and is what matters in cold engines.

Cryogenics and freezing-point measurement (cryoscopy): an old but precise method of determining molecular weight uses the freezing-point depression of camphor (K_f = 40 C kg/mol). Molality is the natural unit.

Osmotic-pressure problems in biology: blood plasma is about 0.3 osmolal (m × i averaged across all dissolved species). IV fluids are designed to match this osmolality so that infused fluid does not draw water out of, or push it into, red blood cells.

Tip

For dilute aqueous solutions you can usually estimate molality from molarity by ignoring the difference. For 0.1 M NaCl, molality is about 0.1 m. As concentration rises or temperature changes, the divergence grows. Above 1 mol/kg, always compute molality from masses for accurate colligative-property work.

FAQ

Molality (m) is the number of moles of solute per kilogram of solvent, units mol/kg. Unlike molarity, which is mol per liter of solution, molality does not change with temperature because mass does not change with thermal expansion.
Divide moles of solute by kilograms of solvent. If you have mass instead of moles, first divide by molar mass to get moles. Example: 5.85 g NaCl (Mr 58.44) in 500 g of water = 0.1 mol / 0.5 kg = 0.2 mol/kg.
Molarity (M) uses liters of solution and changes with temperature. Molality (m) uses kilograms of solvent and is temperature-independent. For dilute aqueous solutions the two values are nearly equal because 1 L of water weighs about 1 kg, but they diverge at higher concentrations and in non-aqueous solvents.
Colligative properties (freezing-point depression, boiling-point elevation, vapor-pressure lowering, osmotic pressure) depend on the number of solute particles per unit of solvent. Because solvent mass does not change with temperature, molality gives a clean, temperature-independent measure of particle concentration.
Delta T_f = K_f m i. K_f is the cryoscopic constant of the solvent (1.86 C kg/mol for water), m is molality, and i is the van't Hoff factor (number of particles per formula unit: 1 for sugar, ~2 for NaCl, ~3 for CaCl2). This is why salt melts road ice: dissolved Na+ and Cl- ions lower the freezing point of the brine.
No. Molality uses the mass of pure solvent, not the mass of the final solution. This is the most common molality error. 100 g of solution that contains 5 g of solute and 95 g of water has 95 g of solvent in the denominator, not 100 g.
A 1 m solution contains 1 mole of solute dissolved in 1 kg of solvent. For aqueous 1 m NaCl: 58.44 g of NaCl + 1000 g (1 L) of water. The final solution volume will be slightly more than 1 L because of the dissolved ions.
Yes. Concentrated solutions can have molalities of 5, 10, or higher. Saturated NaCl at 25 C is about 6.1 mol/kg. The practical upper limit is the solubility of the solute in the chosen solvent at the chosen temperature.